[amsat-bb] Re: future apogee calculation
domenico.i8cvs at tin.it
Fri Feb 26 14:32:40 PST 2010
----- Original Message -----
From: "Bob- W7LRD" <w7lrd at comcast.net>
To: <amsat-bb at amsat.org>
Sent: Thursday, February 25, 2010 6:07 PM
Subject: [amsat-bb] future apogee calculation
> Is there a "easy" way of figuring out where/when a given apogee will at a
> given lat.long?
> 73 Bob W7LRD
Hi Bob, W7LRD
Using InstantTrack it is easy but the procedure is a little bit long.
When you are in the Map Screen push F until you get a phs (phase) of 128
At phs 128 you are at the Apogee and you can read down the map the Lat/long
of the satellite subpoint at the Apogee
If you now push E you will read the keplerian elements on the map screen and
if you push D you can read the derived velues at time.
To day Feb 26 we have:
Perigee Height : 1440.2 km
Apogee Height : 1459.0 km
Latitude of Apogee : -48.9° (South)
Rate of change of Apogee: -1.866 ° / day
Rate of change Argument of Perigee : - 1.957° / day
Now if you want to know the numbar of days that the apogee need to go
from the actual Latitude of - 48.9° South to a wanted Latitude North you
must consider that since the AO7 inclination is greater then 90° the line
of the apsides that join the apogee with the perigee moves in the opposite
direction of the satellite.
As an example:
If you want to know how many days the Apogee needs to go from
the actual Lat of - 48.9° South to a wanted Lat of + 55.0° North the Apogee
must move by 180 + (55.0 - 48.9 ) = 186.1° in the South direction so that
the numbar of days needed are:
186.1° / 1.957° day = 95.09 days from February 26 i.e day 1 june 2010
If you check on any tracking program you will see that AO7 on day 1 june
2010 at 10:17 UTC will be about at phs 128 at Apogee with latitude of about
+ 55° North and longitude 38.0° West with the satellite subpoint at Apogee
just in the middle of the Atlantic ocean.
InstantTrack is a great program if one know how to talk with him !
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